(9)(1/n^2)=36

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Solution for (9)(1/n^2)=36 equation: 


D( n )

n^2 = 0

n^2 = 0

n^2 = 0

1*n^2 = 0 // : 1

n^2 = 0

n = 0

n in (-oo:0) U (0:+oo)

9*(1/(n^2)) = 36 // - 36

9*(1/(n^2))-36 = 0

9*n^-2 = 36 // : 9

n^-2 = 4

-2 < 0

1/(n^2) = 4 // * n^2

1 = 4*n^2 // : 4

1/4 = n^2

n^2 = 1/4 // ^ 1/2

abs(n) = 1/2

n = 1/2 or n = -1/2

n in { 1/2, -1/2 }

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